PFORLOOP-For Loops Challenge

For Loops Challenge

given below code is for pforloop spoj or For Loops Challenge spoj.

only one thing u have to consider number are consecutive .

#include <stdio.h>
#include <algorithm>
using namespace std;
int a[100000];
int main()
{
 int n,i=0,j,end,count=0;
 while(scanf("%d",&n)!=EOF)
 {
  a[i++]=n;
 }
 sort(a,a+i);
 for(j=1;j<=i;j++)
 {
  if(a[j]-a[j-1]==1){
   count++;
  }
  else
  {
   end=a[j-1];
   printf("for (int i = %ld; i <= %ld; i++) cout << i << \" \";\n",end-count,end);
   count=0;
  }
 }
 return 0;
}